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@enu - I recommend you to install the module File::Slurp. You can use read_dir to read all files to an array. Next you probably want to use grep to get the files you want, and sort to sort.
For more information on grep or sort, type on the command line
perldoc -f grepor
perldoc -f sortrespectively.
You can read an entire file with read_file and either print each file to STDOUT and use a redirect when you call your script (i.e. yourscript.pl > output.txt) or use append_file.
See the File::Slurp documentation on CPAN.
Hi, I am writing a perl script using a bunch of xml files. The script is supposed to look at a specific tag in the xml file and read in its text. Its supposed to store the text. As of now, I save the entire the file in a variable and go through each line until i reach the tag which i need. Therefore, if the file is 80000 lines long, the program is certainly not efficient. Can you suggest a quicker way! thanks!
Hi Marta,
The recommended way to parse XML is to use a dedicated XML parser because there are many ways a simple hand coded parser can fail, often in unexpected ways.
While maybe not the best module, XML::Parser might do the job for you. See for an example: XML elements report
This one does parse a bunch of XML files, and it's not that hard to modify the characters sub to remember the text if and only if the opening element has been encountered and use the end_element sub to store the text if and only if the closing element has been encountered.
Remember that the characters sub (handler) can be called several times for a piece of text enclosed in an element.
If you need more help, let me know. I can also write the Perl program for you - because it's a small one - in exchange for book(s), see: Perl programming.
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I need help with Perl. I want to read files within a directory, and print the files content in an ascending order to another file. Any idea how I can do this?